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Coding workflows · Continued-fraction convergents
03
A concrete starting point
Return every convergent of a continued fraction with one through 32 integer coefficients bounded by 1000 in magnitude. Test a negative first term and 3-7-16, rejecting nonpositive later terms and keeping numerator-denominator pairs exact.
Define the change
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Check the outcome
Compare actual behavior with the expected result. If a check fails, investigate it before applying more changes.
Continued-fraction convergents
A concrete starting point
def convergents(terms):
terms = tuple(terms)
if not 1 <= len(terms) <= 32 or any(type(a) is not int or abs(a) > 1000 for a in terms):
raise ValueError("fraction.terms")
if any(a <= 0 for a in terms[1:]):
raise ValueError("fraction.tail")
p0, p1, q0, q1, out = 0, 1, 1, 0, []
for a in terms:
p, q = a*p1+p0, a*q1+q0
out.append((p, q))
p0, p1, q0, q1 = p1, p, q1, q
return outThe example is a starting point for a real project, not a claim that generated code is already tested. Adjust paths, dependencies and expected behavior to match your application.